Physics 4311: Thermal Physics – HW Solution 9


due date: Wednesday, Apr 8, 2026

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Problem 1: Thermodynamic potentials of a surface (10 points)

a)

H = U βˆ’ 𝜎𝐴,𝑑𝐻 = 𝑇𝑑𝑆 βˆ’ π΄π‘‘πœŽ

b)

F = U βˆ’ 𝑇𝑆,𝑑𝐹 = βˆ’π‘†π‘‘π‘‡ + πœŽπ‘‘π΄

c)

G = U βˆ’ 𝑇𝑆 βˆ’ 𝜎𝐴,𝑑𝐺 = βˆ’π‘†π‘‘π‘‡ βˆ’ π΄π‘‘πœŽ

Problem 2: Maxwell relations for a surface (10 points)

a)

from U: (βˆ‚πœŽ βˆ‚π‘† )A = (βˆ‚π‘‡ βˆ‚π΄ )S

b)

from H: (βˆ‚π΄ βˆ‚π‘† )Οƒ = βˆ’ (βˆ‚π‘‡ βˆ‚πœŽ )S

c)

from F: (βˆ‚π‘† βˆ‚π΄ )T = βˆ’ (βˆ‚πœŽ βˆ‚π‘‡ )A

d)

from G: (βˆ‚π‘† βˆ‚πœŽ )T = (βˆ‚π΄ βˆ‚π‘‡ )Οƒ

Problem 3: Response functions of the ideal gas (20 points)

a)

CV = (𝛿𝑄 βˆ‚π‘‡ )V = (βˆ‚π‘ˆ βˆ‚π‘‡ )V = 3 2NkB

b)

Cp = (𝛿𝑄 βˆ‚π‘‡ )p = (βˆ‚π‘ˆ βˆ‚π‘‡ )p + p (βˆ‚π‘‰ βˆ‚π‘‡ )p = 3 2NkB + NkB = 5 2NkB

c)

ΞΊT = βˆ’1 V (βˆ‚π‘‰ βˆ‚π‘ )T = βˆ’1 V (βˆ‚(NkBTβˆ•p) βˆ‚π‘ )T = 1 p

d)

use equation of adaibatic curve pV 5βˆ•3 = const or p3βˆ•5V = A = const
ΞΊS = βˆ’1 V (βˆ‚π‘‰ βˆ‚π‘ )S = βˆ’1 V (βˆ‚(Aβˆ•p3βˆ•5) βˆ‚π‘ )S = 3 5p

e)

Ξ± = 1 V (βˆ‚π‘‰ βˆ‚π‘‡ )p = 1 V (βˆ‚(NkBTβˆ•p) βˆ‚π‘‡ )p = 1 T